Question

find dy\dx of logx by first principal

Answer 1

What is this what should we do

Answer 2

HEY FRIEND HERE YOUR ANSWER

You should know that

lim
k →0 log(1 + k )
k = 1

Then, calling k = h
x , you get

lim
h →0 log(1 + h
x )
h = lim
h →0 log(1 + h
x )
x h
x = 1 ⋅ 1
x =1/x


I HOPE IT'S HELP