Question

Find dy dx of the givenfunctions 1. y = x^n + 2, where n is constant

Answer 1

Answer:

n+2x^n+1

Step-by-step explanation:

this is define by the normal formula of differentiation

who is

d(x^n)/dx = nx^n-1

Answer 2

Answer:

dy/dx= (n+2)x^(n+1)

Step-by-step explanation:

If y= x^n

then, dy/dx= nx^(n-1)

Therefore, here, the question asked is y= x^(n+2)

So, the power is (n+2)

So, we will multiply x by (n+2) and x will be raised to the power ((n+2)-1), which is equal to n+1.

Therefore, here,

dy/dx= (n+2)x^(n+1)...

Hope you will get it...