Question

Find dy/dx of (xy)=(x+y)^2

Answer 1

follow me ........it's detailed solution

Answer 2

Given,
xy = ( x + y) ²

Differentiating both sides with respect to x.

d/dx ( xy) = d/dx ( x + y) ²

x* dy/dx + y * 1 = 2 ( x + y) d/dx ( x + y)

Let dy/dx = y'

xy'+ y = 2 ( x + y) ( 1 + y' )

xy' + y = 2(x + y) y' + 2(x+y)

y' ( x - 2(x + y) = 2(x+y)- y

y' ( x - 2x - 2y ) = 2x + y

y' ( -x - 2y ) = 2x + y

y' = 2x + y / - ( x + 2y )