Question

Find dy/dx of
y=sinx+x²/cot2x​

Answer 1

Step-by-step explanation:

dy/dX=d/dX(sinx)+d/dX(x2.tan2x)

=cosx+x2 d/dX(tan2x)+tan2x d/dX(x2)

=cosx+x2.2.sec2(2x)+tan2x.2x

=cosx+2x.tan2x+2x2.sec2(2x)

Hope it will help you