Question

find dy/dx please fast​

Answer 1

Answer:

2xydy/dx(2y-x^2)-2y-x^2dy/dx(2xy)/(2y-x^2)^2

=2xy(-2x)-x^2(2y)/(2y-x^2)^2

=-4x^2y-2x^2y/(2y-x^2)^2

=-6x^2y/(2y-x^2)^2