Question

Find dy/dx please tell the answer fast

Answer 1

Answer:

Step-by-step explanation:

taking log both side

logy=log(x cotx)^(x+1/x)

logy=(x+1/x) log(x cotx )

logy=(x+1/x) [logx+logcotx ]

x+1/x ki andar multiply karne pr

logy= xlogx + x logcotx + 1/x logx  +1/x logcotx

differentiation karo answer aa jayega ok

and Mark me brainliest ok

Answer 2

Ans

If further simplification needed. You can do it by self.