Question

Find dy/dx:tan-¹x+cot-¹x​

Answer 1

Answer:

f (x) = tan-¹x + Cot-¹ x

Step-by-step explanation:

$\frac{d( { (\tan }^{ - 1}x ) + ( { \cot}^{ - 1} x)) }{dx} \\ = \frac{1}{ {x}^{2} + 1} - \frac{1}{ {x}^{2} + 1 } \\ \\ = 0$

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