Question

find dy/dx
urgent answer
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Answer 1

Answer:

y = 1/(x^2-3x-2)^4

dy/dx = (-4/(x^2-3x-2)^5) * (2x-3)

= -4(2x-3)/(x^2-3x-2)^5

Hope this helps you!

Answer 2

hi my dear friend

here is your answer

y=1 /(x^2-3×-2)^4

Dy/DX=(-4/x^2-3×-2)^5)*(2x-3)

=-4(2x-3)/(x^2-3x-2)^5

hope it will help you

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