find dy/dx. when x=2cosx+cos2x and y=2sinx-sin2x
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Answered by
4
Hope this answer helps
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keerthi1208:
thanks
but the is not the answer
the book back answer for this question is tan3x/2
I don't know how it came
will u please help me by finding the right answer once again
actually something in question is messing me, can u plz. edit the question and make it correct
Answered by
6
Hi ...dear..
here is your solution...
.
dx/dx=-2sinx+2sin2x
dy/dx=2cosx-2cos2x
dy/dx=(dy/dx)/(dx/dx)=(cosx-cos2x)/(-sinx+sin2x)
dy/dx=2sin3x/2.sinx/2/2cos3x/2sinx/2
=tan3x2...
hope this will help you..!!
Regards Brainly Star Community
#shubhendu
here is your solution...
.
dx/dx=-2sinx+2sin2x
dy/dx=2cosx-2cos2x
dy/dx=(dy/dx)/(dx/dx)=(cosx-cos2x)/(-sinx+sin2x)
dy/dx=2sin3x/2.sinx/2/2cos3x/2sinx/2
=tan3x2...
hope this will help you..!!
Regards Brainly Star Community
#shubhendu
sorry
I don't understand the third step dy/dx
i meant the last step before the answer
tan 3x/2
heyyyyyyyy
are you there
please explain it once more
please i can't understand
i request you
i will explain it to you in morning
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