Question

Find dy/dx when (x²/z²)+(y²/b²)=1​

Answer 1

Answer:

-xb^2/z^2y

Step-by-step explanation:

x^2/z^2+y^2/b^2=1

diff w.r.t x

2x/z^2 + 2y/b^2 dy/dx =0

dy/dx = -xb^2/yz^2