Question

find Dy/dx when xy=e^x-y
​

Answer 1

Answer:

log(xy)=log(e

x−y

)

⇒logx+logy=(x−y)

Differentiating both sides with respect to x, we obtain

x

1

+

y

1

dx

dy

=1−

dx

dy

⇒(1+

y

1

)

dx

dy

=1−

x

1

⇒(

y

y+1

)

dx

dy

=

x

x−1

∴

dx

dy

=

x(y+1)

y(x−1)