Physics, asked by faixu3116w, 1 year ago

find dy/dx; when y=(9x^5+4x³)^5

Answers

Answered by sourashishpatra02

$\frac{dy}{dx} = 5(9x^{5} + 4x^{3})^{4} \times 36x {}^{4} + 8x {}^{2}$

faixu3116w: Bro please explain

whatever28: this has a formula .. wait a sec

faixu3116w: Okk

whatever28: if y = (ax + b ) ^n then dy÷dx = n (ax +b) ^n-1 (a)

whatever28: hope this is helpful

faixu3116w: Okk bro

faixu3116w: Thanks

faixu3116w: Bro please again help me

Answered by whatever28

dy÷dx = 5 (9x^5 + 4x^3)×45x^4+12x^2

faixu3116w: Bro i dont understand this please help me

whatever28: dude you still didn't get it ?

faixu3116w: Noo

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