Question

find dy/DX when y=e^x(1+ logx)​

Answer 1

Answer:

Step-by-step explanation:

Given,

y=e  

(1+log  

e

​  

x)

 

or, y=e.e  

log  

e

​  

x

 

or, y=e.x

Now, differentiating both sides with respect to x we get,

dx

dy

​  

=e.