Question

find dy/dx when y=lnx/x​

Answer 1

Answer:

Answer:

y

'

=

ln

(

x

)

ln

(

x

)

⋅

(

1

x

⋅

ln

(

ln

(

x

)

)

+

1

x

)

Explanation:

Taking the logarithm on both sides we get

ln

(

y

)

=

ln

(

x

)

⋅

ln

(

ln

(

x

)

)

differentiating with respect to

x

:

y

'

y

=

1

x

ln

(

ln

(

x

)

)

+

ln

(

x

)

⋅

1

ln

(

x

)

⋅

1

x

so we get

y

'

=

ln

(

x

)

ln

(

x

)

⋅

(

1

x

ln

(

ln

(

x

)

)

+

1

x

)

Explanation:

please mark brainliest