Question

Find dy/dx when

y=log√(1 - cosx/1+cosx)+a^x



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Answer 1

Step-by-step explanation:

y=u + v

dy/ dx = du/ dx + dv / dx

now ,u=log√(1 - cosx/1+cosx)

u=log tan(x/2)

du/dx. =log tan(x/2)