Question

find dy/dx when y= (x-1)(2x+8)​

Answer 1

Answer:

We have,

y=x+x1

 

On taking differentiating both sides w.r.t x, we get

dxdy=2x1−2(x)231

 

Since, x=1

 

Therefore,

dxdy∣∣∣∣∣x=1=211−2(1)231

dxdy∣∣∣∣∣x=1=21−21

dxdy

Answer 2

Answer:

$y = (x - 1)(2x + 8)$

$\frac{dy}{dx} = vu {}^{1} + uv {}^{1}$

$= (2x + 8) \frac{d(x - 1)}{dx} + ( x - 1) \frac{d(2x + 8)}{dx}$

$\frac{dy}{dx} =( 2x + 8).1 +( x - 1).2$

$\frac{dy}{dx} =( 2x + 8 )+ (2x - 2)$

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