Question

find dy/dx when y=(x-1)(x-2)/√x​

Answer 1

Answer:

Y=x²-3x+2/√x

by quotient rule y'= N'D- D'N/D²

we will differentiate N first =2x-3

we will differentiate D = 1/2 √x

now dy/dx

dy/dx=[√x.(2x-3)-1/2√x.(x²-3x+2)]/√x²

dy/dx =[2x(2x-3)-(x²-3x+2)]/2x√x.x

dy/dx =[4x²–6x-x²-3x+2]/2x√x.

dy/dx=(3x²–3x-2)/2.x.√x.

hey I am new in class 11 and learned differential claculus so well .It took some time but i solved