Question

find dy/dx when y=x*x

Answer 1

x*x^x-1
* refers to multiplication

Answer 2

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$y = {x}^{x} \\ so \: takig \: lo g \: both \: sides \\ logy = log {x}^{x} \\ logy = xlogx \\ diffrentiate \: wrt \: x \: \: \\ \frac{1}{y} \ \frac{dy}{dx} = x \times \frac{1}{x} + logx \\ \frac{dy}{dx} = y(1 + logx) \\ but \: we \: know \: y = {x}^{x} \\ so \: \frac{dy}{dx } = {x}^{x} (1 + logx)$
hope it will help u