Math, asked by shobhamalik109, 1 month ago

Find dy/dx when y = x^x.

Answers

Answered by imstoopid
0

Answer:

y = x^x

log on bs

log y = xlogx

differentiate

1/y dy/dx = x(1/x)+logx

dy/dx = y(1+logx)

dy/dx = x^x(1+logx)

feel free to correct me if I'm wrong:)

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