Question

find dy/dx when
y=x5+x4+7
​

Answer 1

Answer:

y= x^5 + x^4+ 7

so dy/dx = 5*(x^4) + 4*(x^3)

Answer 2

Given:

A function $y=x^{5}+ x^{4}+7$

To find:

Value of $\frac{dy}{dx}$ for the given function

Solution:

We have,

$y=x^{5}+ x^{4}+7$

Differentiating both sides of the equation, we get

$\frac{dy}{dx}=\frac{d(x^{5}+ x^{4}+7 )}{dx}$

$\frac{dy}{dx}=\frac{dx^{5} }{dx} +\frac{dx^{4} }{dx}+\frac{d7}{dx}$

We know, for $y=x^{n}$   ,  $\frac{d(x^{n} )}{dx}= nx^{n-1}$

and for $y=constant$   , $\frac{d(k)}{dx} =0$

Hence,

$\frac{dy}{dx}=5(x^{4} ) +4(x^{3} )+0$

$\frac{dy}{dx}=5x^{4} +4x^{3}$

Final answer:

Hence, the differentiation of $x^{5}+ x^{4}+7$ with respect to $x$ is $5x^{4} +4x^{3}$