Question

Find dy/dx where:
1) y=x^5/2 - 5/x^2
2)y=1/root x
3)y=1/x+3

Answer 1

Answer:

• dy/dx = 5/2x^3/2 + 10/x³

• dy/dx = -1/2x^(-1/2-1) = -1/2*x^-3/2 = -1/(2x^3/2)

• dy/dx = log(x+3)

Answer 2

Answer:

dy/dx = 5/2x^3/2 + 10/x³

dy/dx = -1/2x^(-1/2-1) = -1/2*x^-3/2 = -1/(2x^3/2)

dy/dx = log(x+3)

hope it helps u