Question

find dy/dx where ax²-2hxy +bx²=1 ​

Answer 1

Step-by-step explanation:

We have,

$a {x}^{2} - 2hxy + b {y}^{2} = 1$

$\implies2ax - 2hy - 2hx \frac{dy}{dx} + 2by \frac{dy}{dx} = 0$

$\implies \: ax - hy - hx \frac{dy}{dx} + by \frac{dy}{dx} = 0$

$\implies(ax - hy) = (hx - by) \frac{dy}{dx}$

$\implies \frac{dy}{dx} = \frac{ax - hy}{hx - by}$