Find dy/dx X^3 + Y^3 equal to 27
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Answer:
x^3+y^3=27
differentiating both sides, we get
d/dx(x^3+y^3=27)
3x^2+3y^2dy/dx=d/dx(27)
3x^2+3y^2dy/dx=0
3y^2dy/dx=-3x^2
dy/dx=-3x^2/3y^2
dy/dx=-x^2/y^2
dy/dx=-x^2y^-2
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