find dy/dx, x= a ( costheta + thetasintheta ), y = a (sintheta + thetacostheta)
plz ans correctly and dont spam .... its similar to class 12th book ques but the signs are diff
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Answer:
Tan θ
Step-by-step explanation:
Given x= a ( costheta + thetasintheta ), y = a (sintheta + thetacostheta)
dy / d thetha = a(cosθ−cosθ+θsinθ)=a(θsinθ)
Similarly , we get dθ / dx = a(−sinθ+sinθ+θcosθ)=a(θcosθ)
⟹ dy / dx = aθsinθ / aθcosθ = tanθ
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Answer:
hello sis/bro you are on after a long time
:)
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