Find dy/dx; x = at^3 , y=3at
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000000000000000
Step-by-step explanation:
9999999+99999999999999999-9999999999999999+99999999999×999999999999999÷000000000000000×0000))
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Given that :
y =3at ... (1)
And x = at^3 ... (2)
Differentiate w. r. t. t of equ. (1) :
dy/dt = 3a ... (3)
Differentiate w. r. t. t of equ. (2) :
dx/dt = 3at^2 (4)
On dividing equ. (3) by (4) :
(dy/dt)/(dx/dt) = 3a/3at^2
=> dy/dx = 1/t^2
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