Question

find dy/dx
x= yln(x-y)

Answer 1

Answer: dy/dx = 1 / (ln(x-y)+y/(x-y))

Step-by-step explanation:

x = y ln(x-y)

1 =  y' ln(x-y) + y (1/(x-y)) (-y')

1 = y' (ln(x-y) + y(1/(x-y))

y' = 1 / (ln(x-y)+y/(x-y))