find dy÷dx. y= cos‐¹2x÷1+x²
Answers
Answered by
0
Step-by-step explanation:
y=cos
−1
(
1+x
2
2x
)=
2
π
−sin
−1
(
1+x
2
2x
)
Put x=tanθ⇒y=
2
π
−sin
−1
(
1+tan
2
θ
2tanθ
)
⇒y=
2
π
−sin
−1
sin(2θ)=
2
π
−2θ
⇒y=
2
π
−2tan
−1
x∴
dx
dy
=−
1+x
2
2
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