Math, asked by avantikasingh15447, 1 month ago

find dy÷dx. y= cos‐¹2x÷1+x²​

Answers

Answered by bhimadevi604
0

Step-by-step explanation:

y=cos

−1

(

1+x

2

2x

)=

2

π

−sin

−1

(

1+x

2

2x

)

Put x=tanθ⇒y=

2

π

−sin

−1

(

1+tan

2

θ

2tanθ

)

⇒y=

2

π

−sin

−1

sin(2θ)=

2

π

−2θ

⇒y=

2

π

−2tan

−1

x∴

dx

dy

=−

1+x

2

2

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