Question

find dy/ dx, y= sec^2 (e^x)​

Answer 1

$y = {sec}^{2} {e}^{x} \\ \frac{dy}{dx} = 2sec ({e}^{x} ) \frac{d}{dx} sec( {e}^{x} ) \\ = 2sec( {e}^{x} ).sec( {e}^{x} )tan( {e}^{x} ). {e}^{x} \\ = 2 {e}^{x} {sec}^{2} ( {e}^{x} )tan( {e}^{x} )$