Math, asked by sakshamsingh312448, 9 months ago

find dy/dx
y sec x + tan x +x²y = 0​

Answers

Answered by Anonymous
0

Answer:  y sec x + tan x + x2y = 0

differentiating both sides with respect to x

, we get⇒y . sec x tan x + sec x . dy/dx + sec^2x + x^2dydx + y . 2x = 0

⇒(sec x + x^2)dy/dx = −2xy − sec^2x − y sec x . tan x

⇒dy/dx = −(y sec x tan x + sec^2x + 2xy)/(sec x + x^2)

Step-by-step explanation:

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