Question

find dy/dx
y= sec² √tanx​

Answer 1

Answer:

Please mark me as brainliest ✨

Answer 2

$y = {sec}^{2} \sqrt{tanx} \\ \\ \frac{dy}{dx} = 2secx \sqrt{tanx} . \frac{1}{2 \sqrt{tanx} } . {sec}^{2} x \\ \\ \frac{dy}{dx} = {sec}^{3} x$