find dy/dx=? y=(sin-¹x²)².
Answers
Answered by
2
Answer:
y=(sin−1x)2
on differentiating wrt x we get
⇒dxdy=2sin−1x×1−x21 _______ (1)
again differentiating wrt x we get
⇒dx2d2y=2(1−x2)1−x21×1−x2−sin−1×21−x21x−2x
(1−x2)dx2d2y=2[1+x1−x2sin−1x]
(1−x2)dx
Answered by
121
Answer:
The best way of learning is to download brainly app now.
hope it helps
Similar questions