English, asked by anjalinetam2909, 4 months ago

find dy/dx=? y=(sin-¹x²)².​

Answers

Answered by prabhat211
2

Answer:

y=(sin−1x)2

on differentiating wrt x we get

⇒dxdy=2sin−1x×1−x21 _______ (1)

again differentiating wrt x we get

⇒dx2d2y=2(1−x2)1−x21×1−x2−sin−1×21−x21x−2x

(1−x2)dx2d2y=2[1+x1−x2sin−1x]

(1−x2)dx

Answered by Rehanlover
121

Answer:

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