Find dy/dx:
y = (sin✓x)^3
Answers
Answered by
3
Answer:
y=sin−1(x1−x−−−−−√+x−−√1−x2−−−−−√)→(1)
Let x=sinθ
Then, cosθ=1−x2−−−−−√
Let x−−√=sinϕ
then, cosϕ=1−x−−−−−√
Putting these values in (1),
⇒y=sin−1(sinθcosϕ+cosθsinϕ)
⇒y=sin−1(sin(θ+ϕ))
⇒y=θ+ϕ
⇒y=sin−1x+sin−1x−−√
Now, differentiating both sides w.r.t. x,
⇒dydx=11−x2−−−−−√+11−x−−−−−√∗12x−−√
⇒dydx=11−x2−−−−−√+12x(1−
Step-by-step explanation:
Similar questions