Math, asked by Deepankar7, 4 months ago

Find dy/dx:

y = (sin✓x)^3

Answers

Answered by BrainlyAryabhatta
3

Answer:

y=sin−1(x1−x−−−−−√+x−−√1−x2−−−−−√)→(1)

Let x=sinθ

Then, cosθ=1−x2−−−−−√

Let x−−√=sinϕ

then, cosϕ=1−x−−−−−√

Putting these values in (1),

⇒y=sin−1(sinθcosϕ+cosθsinϕ)

⇒y=sin−1(sin(θ+ϕ))

⇒y=θ+ϕ

⇒y=sin−1x+sin−1x−−√

Now, differentiating both sides w.r.t. x,

⇒dydx=11−x2−−−−−√+11−x−−−−−√∗12x−−√

⇒dydx=11−x2−−−−−√+12x(1−

Step-by-step explanation:

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