Question

find dy/dx, y=(sinx+√x)​

Answer 1

Please find the above attached image

steps

$y = \sin(x) + \sqrt{x}$

$= \sin(x) + {x}^{ \frac{1}{2} }$

therefore

$\frac{dy}{dx} = \cos(x) + \frac{1}{2} {x}^{ - \frac{1}{2} }$

$= \cos(x) + \frac{1}{2 \sqrt{x} }$