Question

Find dy/dx :-y= x^3 - 3x^2 + 3x-2/5​

Answer 1

Answer:

y= x^3 - 3x^2 + 3x-2/5

Explanation:

y= x^3 - 3x^2 + 3x-2/5

If x + y² + sin (y)2 = 0 , find dy/dx

[ - 4 x3y/( 2 x 4 + 2 cos y2)]

Answer 2

Answer:

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y= x^3 - 3x^2 + 3x-2/5

Explanation:

y= x^3 - 3x^2 + 3x-2/5

If x + y² + sin (y)2 = 0 , find dy/dx

[ - 4 x3y/( 2 x 4 + 2 cos y2)]

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