Question

find dy/dy if y=sin x / tan x?

Answer 1

y=sin/tanx
y= sinx/( sinx/cosx) [tanx=sinx/cosx]
y=cosx
now on derivation we get,
dy/dx= -sinx
Hope you understood the answer. If so,mark me

Answer 2

$y = \frac{sinx}{tanx} \\ \\ \frac{dy}{dx} = \frac{tanxcosx - sinx {sec}^{2}x }{ {tan}^{2} x} \\ \\ \frac{dy}{dx} = \frac{sinx - tanxsecx}{ {tan}^{2} x}$