Find
dy
if, i) x^2 + 2xy + y^2 = 0
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Answer:
dy = A /(x + y)
Step-by-step explanation:
dy(x^2 + 2xy + y^2)=dy(0)
0 + 2x dy + 2y dy = k. where k is constant
(2x + 2y) dy = k
dy = k / (2x + 2y)
dy = A / ( x + y). where A = k/2
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