Find dylda:
2x+3y=sinx
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Step-by-step explanation:
★ DIFFERENTIATION ★
Given function to be differentiated :
2x + 3y = Sin x
d 2x / dx + d 3y / dx = d Sinx / dx
2 + 3dy/dx = Cosx
Hence , dy/dx = Cosx-2/3
It can be solved by using insertion of TRIGONOMETRIC and LOGARITHMIC functions too , but it'll result the same as above described
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