find each angle of an isosceles triangle whose one angle is 4 times the other equal angle?
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let the equal angles be x.
so, according to the question -
4x + x + x = 180
6x = 180
x = 180/6 = 30
so equal angles will be 30 degrees
and the unequal angle will be 120 degrees
so, according to the question -
4x + x + x = 180
6x = 180
x = 180/6 = 30
so equal angles will be 30 degrees
and the unequal angle will be 120 degrees
Saloni:
thanks
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