Question

Find each missing value

a) (√24-√k)(√24+√k)=5

b)√32-√s=-4√2​

Answer 1

${\color{lightpink}{AN}}{\color{blue}{SW}}{\color{purple}{ER:}}$

a)

$( \sqrt{24} - \sqrt{k } )(\sqrt{24} + \sqrt{k }) = 5 \\ \\ here.(a - b)(a + b) = {a}^{2} - {b}^{2} \\ \\ ( { \sqrt{24} ) }^{2} - ( { \sqrt{k} )}^{2} = 5 \\ \\ 24 - k = 5 \\ \\ 24 - 5 = k\\ \\ {\boxed{\pink{19 = k}}}$

b)

$\sqrt{32} - \sqrt{s} = - 4 \sqrt{2} \\ \\ simplify \: \sqrt{32} = 4 \sqrt{2} \\ \\ 4 \sqrt{2} - \sqrt{s} = - 4 \sqrt{2} \\ \\ { \cancel{4 \sqrt{2 }}} = { \cancel{ - 4 \sqrt{2}}} + \sqrt{s} \\ \\ 0 = \sqrt{s} \\ \\ \sqrt{0} = s \\ \\ {\boxed{\pink{ 0 = s}}}$

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Answer 2

Answer:

pls see I attached the answer