Find each no of atoms present in 0.5 mole of cane sugar
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So, one mole of a substance contains exactly the Avogadro number (N) of particles. Where NS is the number of molecules in the substance. It is given to us that there are 0.5 moles of glucose present. Hence, there are 3.011×1023 molecules in 0.5moles of glucose.
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Answer:
mass of C=12u mass of H = 1u mass of O = 16u
amu of sugar =(12*12) + (1*22) + (16*11)
= 144 + 22 + 176 = 342u
molar mass = 342 grams
mass = no. of moles * moles mass = 0.5*
342 = 171 grams
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