Question

find each of the angles of the triangle ABC in the adjoining figure where BA||CE.​

Answer 1

Answer:

As we know, Angle on a straight line is 180°

⇒ ∠ECD + ∠ECB + ∠ACB = 180°

80° + 40° + ∠ACB = 180°

120° + ∠ACB = 180°

∠ACB = 180 -120

∠ACB = 60°

As, AB║CE

⇒ ∠ABC = ∠ECD = 80°     { Corresponding angles }

∴ ∠ABC = 80°

Now in triangle ABC:

Sum of all angles of Δ = 180°

∠ABC + ∠ACB + ∠BAC = 180°

80° + 60° + ∠BAC = 180°

140° + ∠BAC = 180°

∠BAC = 180° -140°

∠BAC = 40°

Step-by-step explanation:

Hope it helps you buddy :)

Answer 2

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