find each of the following product
(3y-8)×(5y-1)
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Answered by
9
Answer:
By using horizontal method,
We have;
= (3y - 8) × (5y - 1)
= 3y(5y – 1) – 8(5y – 1)
= 15y2 – 3y – 40y + 8
= 15y2 – 43y + 8
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Welcome to my answer
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The product of the following question is :
(3y-8) x (5y-1)
= 15y^2-3y-40y+8 (quadratic equation)
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