Question

Find each of the following products.
i) 3 × -1 ii) -21×-3 iii) (-3) × (-6) ×(-2)
iv) (-15) ×0 × (-8) vi ) (-1) × (-2) × (-3) × 4
Find the following products.
i) 3 × (-10) ii) (-4) × (-5) × (-7) iii) (-20) ×(-30) × (-20)
Evaluate each of the following:
i) (-30) ÷ 10 ii) 36 ÷ (-9) iii) (-31) ÷[(-30)+ (-1) ]
Fill in the blanks ‘>’ , ‘<’ or ‘=’ sign.
i) (-3) + (-6) ______ (-3) – (-6) ii) 45 + (-11) ______ 57 + (-4)
ii) (-25)+(-42) ______ (-42)-(-25) iii) (-21)+(-10)______(-31) – (-11)
Find the value of [ (-16) × (-3)] ÷ [(-12) ×4 ].
The value of (-8) ×[ (-7) - (-5) ].
The product of two numbers is -82.If one of them is -2 then find the other number.
X
-2
-1
0
1
2

-2






-1






0






1






2






In the below given table, fill in each box with the product of the integers representing the corresponding row and corresponding column.​

Answer 1

Find each of the following products :

i) 3 × -1 = -3

ii) -21×-3 = 63

iii) (-3) × (-6) ×(-2) = -36

iv) (-15) ×0 × (-8) = 0

vi ) (-1) × (-2) × (-3) × 4 = -24

Find the following products :

i) 3 × (-10) = -30

ii) (-4) × (-5) × (-7) = -140

iii) (-20) ×(-30) × (-20) = -12000

Evaluate each of the following:

i) (-30) ÷ 10 = -3

ii) 36 ÷ (-9) = -4

iii) (-31) ÷[(-30)+ (-1) ] = -31 ÷ (-31) = 1

Fill in the blanks ‘>’ , ‘<’ or ‘=’ sign :

i) (-3) + (-6) < (-3) – (-6)

ii) 45 + (-11) < 57 + (-4)

iii) (-25)+(-42) < (-42)-(-25)

iv) (-21)+(-10) < (-31) – (-11)

Find the value of :

i) [ (-16) × (-3)] ÷ [(-12) ×4 ] = 48 ÷ (-48) = -1

ii) (-8) ×[ (-7) - (-5) ] = -8 × (-2) = 16

The product of two numbers is -82.If one of them is -2 then find the other number

Solve : Let, the number be x

ATQ : (-2) × x = (-82)

=> x = -82/(-2) = 41

So, the other number will be 41 ✔

______________________________

Hope it helps ☺

Fóllòw Më ❤