Question

Find each of the multiples,
Three numbers are in the ratio 3:4:5. If the sum of the largest and the smallest numbers exceeds the
third number by 64, find the numbers.
The denominator of a rational number is greater than its numerator by 5. If the numeratoris increased​

Answer 1

Correct question:- Three numbers are in the ratio 3:4:5. If the sum of the largest and the smallest numbers exceeds the third number by 64, find the numbers.

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Given:

• The ratio = 3:4:5
• Sum of largest and smallest number exceeds the third number by 64.

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Need to find:

• The three numbers =?

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Soluton:

• Let the common multiple of the tree numbers be x

Then the three numbers will be:

• 3x
• 4x and
• 5x

Clearly 5x will be the largest number and 3x will be the smallest number.

According to the question,

5x+ 3x = 64+ 4x

→ 8x = 64+ 4x

→ 8x - 4x = 64

→ 4x = 64

→ x = 64÷ 4

→ x = 16

Then the tree numbers will be:

• 3x = 3×16 = 48
• 4x= 4× 16 = 64
• 5x= 5 ×16 = 80

∴The three numbers are 48, 60 and 80.

Answer 2

Answer:

48, 60 and 80 are the three numbers

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