find each side of an equilateral triangle having area 9 root 3
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Let a be the side of triangle,
Area = root3 /4 a2
9root3=root3/4a2
9root3*4/roo3=a2
So,9*4=a2
36=a2
Hence, a=6units
The side of triangle is 6units
Hope it helps you dear..
Area = root3 /4 a2
9root3=root3/4a2
9root3*4/roo3=a2
So,9*4=a2
36=a2
Hence, a=6units
The side of triangle is 6units
Hope it helps you dear..
Answered by
1
Area of equilateral triangle is (a³√3/4), where a is the side of the equilateral triangle.
a²√3/4 = 9√3
root 3 gets cancelled on both sides
a²/4 = 9 => a²= 9*4 = 36 units
=> a =√36 = 6 units - side of that triangle
Hope it helps!!
Cheers!!
a²√3/4 = 9√3
root 3 gets cancelled on both sides
a²/4 = 9 => a²= 9*4 = 36 units
=> a =√36 = 6 units - side of that triangle
Hope it helps!!
Cheers!!
Steph0303:
pls mark it as brainliest answer
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