Question

Find EH.
and write the answer below

Answer 1

draw a perpendicular from O on EH at A
now in ∆ OAF
AF = 5 cm....( perpendicular from centre to chord bisects the chord)
OF = 13 cm (radius of circle)
by applying Pythagorean theorom we get
${oa}^{2} + {af}^{2} = {of}^{2}$
oa = 12 cm
now in ∆ OAE
0A = 12 cm
OE = 20 cm
again applying Pythagorean theorom
so AE = 16 cm
Now if AE is 16 cm
then EH should be 2(16) cm = 32 cm
(bisected at A)
hope this helps...

Answer 2

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