Question

find electric field at a distance 1 from charge 1 NC​

Answer 1

$\color{darkblue}\underline{\underline{\sf Given-}}$

• Distance (r) = 1m
• Charge (Q) = 1μC

$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

• Electric Field (E)

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❏ Electric Field

$\color{violet}\bullet\underline{\boxed{\sf E=\dfrac{1}{4π\epsilon_o}×\dfrac{Q}{r^2}}}$

$\color{orange}\implies{\sf \dfrac{1}{4π\epsilon_o}=9×10^9\:Nm^2/C^2 }$

$\implies{\sf E = 9×10^9×\dfrac{10^{-6}}{1^2}}$

$\color{red}\implies{\sf E=9×10^3\:V/C }$

$\color{darkblue}\underline{\underline{\sf Answer-}}$

Electric Field will be $\color{red}{\sf 9×10^3\:V/C}$

Answer 2

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

• Distance (r) = 1 m
• Charge (q) = 1 micro C or 1 × (10)^-6 C

We know that , the electric field at a point at a distance r from a charge q is given by

$\large \mathtt{ \fbox{ \vec{E} = k \frac{q}{ {(r)}^{2} } }}$

Where , K = 9 × (10)^9 Nm²/C²

Thus ,

$\sf \mapsto \vec{E} = \frac{9 \times {(10)}^{9} \times1 \times {(10)}^{ - 6} }{ {(1)}^{2} } \\ \\ \sf \mapsto \vec{E} = 9 \times {(10)}^{3} \: \: N/C$

Hence , the electric field is 9 × (10)³ N/C

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