Find electric field at any point on dipole seprated by a small distance 2a? Derive✌️
JinKazama1:
But, Question seems to ask along the dipole
Answers
Answered by
19
Final Answer :
This Electric field is in polar - Co ordinate at any general angle
Understanding:
1) Electric Field on the axis of a dipole is
where p is dipole vector.
2) Electric field on the equatorial axis is
where p is dipole vector.
These Identities will be used in derivation.
Steps :
1) We will take any general point (r,/theta) .
2) We will find Electric field at point by taking components of dipole vector along and parallel to (r) vector.
3) For Along, r vector will use identity for axis Electric Field by dipole.
4) For Perpendicular to (r), we will use Identity for Equatorial Field by angle (r) .
5) Then, we will find
E(res) = √ ( E (p) ^2 + E(A)^2)
where
E(p) = Electric field perpendicular to (r) vector.
E(A) = Electric Field along (r) vector.
For Calculation see pic
This Electric field is in polar - Co ordinate at any general angle
Understanding:
1) Electric Field on the axis of a dipole is
where p is dipole vector.
2) Electric field on the equatorial axis is
where p is dipole vector.
These Identities will be used in derivation.
Steps :
1) We will take any general point (r,/theta) .
2) We will find Electric field at point by taking components of dipole vector along and parallel to (r) vector.
3) For Along, r vector will use identity for axis Electric Field by dipole.
4) For Perpendicular to (r), we will use Identity for Equatorial Field by angle (r) .
5) Then, we will find
E(res) = √ ( E (p) ^2 + E(A)^2)
where
E(p) = Electric field perpendicular to (r) vector.
E(A) = Electric Field along (r) vector.
For Calculation see pic
Attachments:
Answered by
5
Explanation:
Steps :
1) We will take any general point (r,/theta) .
2) We will find Electric field at point by taking components of dipole vector along and parallel to (r) vector.
3) For Along, r vector will use identity for axis Electric Field by dipole.
4) For Perpendicular to (r), we will use Identity for Equatorial Field by angle (r) .
5) Then, we will find
E(res) = √ ( E (p) ^2 + E(A)^2)
where
E(p) = Electric field perpendicular to (r) vector.
E(A) = Electric Field along (r) vector.
For Calculation see pic
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