Physics, asked by řåhûł, 1 year ago

Find electric field at any point on dipole seprated by a small distance 2a? Derive✌️


JinKazama1: But, Question seems to ask along the dipole
raminder1: no
řåhûł: Electric field at any point not on equatoriol line or on axis of dipole
raminder1: hmm
raminder1: rahul ur result of class 11?
JinKazama1: Means At particular angle theta.
raminder1: hmm
raminder1: rahul plz reply to my Q
řåhûł: 82
řåhûł: 12th*

Answers

Answered by JinKazama1
19
Final Answer :
 \frac{kp}{ {r}^{3} }  \sqrt{1 + 3 { (\cos( \theta)})^{2} }

This Electric field is in polar - Co ordinate at any general angle
(r. \theta)

Understanding:
1) Electric Field on the axis of a dipole is
 \frac{2kp}{ {r}^{3} }
where p is dipole vector.

2) Electric field on the equatorial axis is
  \frac{ - kp}{ {r}^{3} }

where p is dipole vector.

These Identities will be used in derivation.


Steps :
1) We will take any general point (r,/theta) .
2) We will find Electric field at point by taking components of dipole vector along and parallel to (r) vector.
3) For Along, r vector will use identity for axis Electric Field by dipole.
4) For Perpendicular to (r), we will use Identity for Equatorial Field by angle (r) .
5) Then, we will find
E(res) = √ ( E (p) ^2 + E(A)^2)
where
E(p) = Electric field perpendicular to (r) vector.
E(A) = Electric Field along (r) vector.


For Calculation see pic

Attachments:

raminder1: jin
JinKazama1: ..
Answered by xXKaminiKanyaXx
5

Explanation:

Steps :

1) We will take any general point (r,/theta) .

2) We will find Electric field at point by taking components of dipole vector along and parallel to (r) vector.

3) For Along, r vector will use identity for axis Electric Field by dipole.

4) For Perpendicular to (r), we will use Identity for Equatorial Field by angle (r) .

5) Then, we will find

E(res) = √ ( E (p) ^2 + E(A)^2)

where

E(p) = Electric field perpendicular to (r) vector.

E(A) = Electric Field along (r) vector.

For Calculation see pic

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