Physics, asked by pushplatabehera25, 1 month ago

Find electric potential difference between the two point in an electric field of strength 300N/C. The distance between the two point is 5m.

Answers

Answered by IshitaAgarwal05

1

Answer:

1500 Volt

Explanation:

V = Ed = 300 x 5 = 1500 Volt

Hope it helps.

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