find electrical resistance of 60W lamp operated on 220 volts
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Answered by
3
P = VI.
60 = 220 x I,
I = 60 / 220,
I = 0.273A.
V = IR.
220 = 0.273 x R
R = 220 / 0.273
R = 805.86ohms
Answered by
3
Answer:
Explanation:
we know that
P=V²/R
P=60 W
V=220 V
R=V²/R
=220*220/60
=806.67 Ω
Hope this helps.
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